python暴力破解压缩包密码 源码

代码如下，自行试用，不得用于非法

import rarfile
import zipfile
import py7zr
c = 0
a = 0
print("本软件只支持 7z , zip , rar格式的压缩包")
zd = input("请输入字典位置：")
try:
ozd = open(zd,"r",encoding="utf8").read().split("\n")
except:
print("字典读取失败")
print(f"检测到字典里有{len(ozd)}个密码")
file = input("请输入要破解的压缩包位置：")
if file.endswith(".zip"):
print("检测到是zip压缩包")
print("正在破解.....")
zip = zipfile.ZipFile(file)
for pas in ozd:
c = c + 1
pasw = bytes(pas.encode("utf8"))
try:
zip.extractall(pwd=pasw)
print("破解成功，密码是：" + pas)
a = a + 1
break
except:
pass
if a == 0:
print("破解失败")
elif file.endswith(".rar"):
print("检测到是rar压缩包")
print("正在破解.....")
rar = rarfile.RarFile(file)
for pas in ozd:
c = c + 1
pasw = bytes(pas.encode("utf8"))
try:
rar.extractall(pwd=pasw)
print("破解成功，密码是：" + pas)
a = a + 1
break
except:
pass
if a == 0:
print("破解失败")
elif file.endswith(".7z"):
print("检测到是7z压缩包")
print("正在破解.....")
for pas in ozd:
c = c + 1
pasw = bytes(pas.encode("utf8"))
try:
qz = py7zr.SevenZipFile(file,password=pasw)
qz.extractall()
print("破解成功，密码是" + pas)
a = a + 1
break
except:
pass
if a == 0:
print("破解失败")
else:
print("此文件不是压缩包文件")
print(f"已经尝试了{c}个密码")
input("破解完成，请按任意键继续.....")